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# Exploring Integrals from the Putnam Competition

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Chapter 1: Introduction to Putnam

The Putnam competition is a prestigious mathematical contest, primarily held in North America, aimed at undergraduate students. It presents a series of challenging problems that test the limits of mathematical reasoning. Today, we will analyze one of these intriguing problems.

Integral limit problem from the Putnam competition

Section 1.1: Problem Overview

For this particular problem, known as Putnam 2008 B2, we begin by examining a few small values of n with a variable x. We find that F_0(x) is expressed as log(x), and F_1(x) is represented as x log x - x = x(log x - 1). To simplify our calculations, let’s compute the integral of x^n log x using integration by parts, which yields:

Integration by parts application

This results in the following:

Simplified expression from integration

From our computations, we can infer a pattern. The logarithmic function remains constant, and the exponent of x consistently increases by one. Notably, the denominator appears to be multiplied by the subsequent integer. Thus, we can hypothesize the following form for F_n(x):

Hypothesized form for F_n(x)

Section 1.2: Deriving a_n

Now, we need to determine the value of a_n while confirming that each F_n(x) adheres to the same structure. By integrating and applying the formula we derived, we find that F_(n+1)(x) can be expressed as:

Expression for F_(n+1)(x)

Consequently, we discover that a_n represents the sum of the first n reciprocals. With this knowledge, we can proceed to tackle the problem itself. Plugging this into our limit gives us:

Limit expression for the problem

Given that log(1) equals 0, we now focus on evaluating this new limit. While it may be tempting to equate this to 0 due to the summation of constants over an infinite range, it’s crucial to remember the infinite nature of those constants.

Section 1.3: Establishing Bounds

To analyze a_n, we need to establish bounds. Notice that 1/x is a strictly decreasing function for positive x, allowing us to derive:

Lower bound for a_n

Next, we will explore an upper bound using a similar approach:

Upper bound for a_n

As n approaches infinity, the impact of these constants diminishes; thus, we can disregard them. Therefore, our limit simplifies to:

Simplified limit result

Ultimately, we arrive at our conclusion.

Final result of the integral limit

Exploring Additional Resources

For further insights into the techniques used in this problem, here are some recommended videos:

This video titled "Maximizing an Integral | Putnam 2006 B5" delves into integral maximization strategies that can enhance your understanding of similar problems.

Another useful resource is "Squeeze Theorem | Integration by Parts | Limits | Calculus | Putnam 2011 Problem A3," which covers foundational calculus concepts relevant to solving Putnam problems.

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